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Candidates preparing for JEE Advanced 2026 can download the official syllabus PDF from jeeadv.ac.in, released by IIT Roorkee.

Solution: det (A) = −5, and for n×n matrix adj (A) has determinant (det A)^ (n−1). Here n = 3, so det (B) = (−5)^ (2) = 25.

Find the marks-wise important questions for CBSE Class 12 Maths board exam 2024 below. 1. The corner points of the bounded ...

The Australian Association of National Advertisers (AANA) has reinforced its role in shaping the future of Australian ...

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